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5th IGO Problems.pdf

Problems-and-Solutions-Elementary.pdf

🔗 Source: rl.kiev.ua

📊 Size: 728 KB

📄 Pages: 8 pages

⬇️ Downloads: 143

Summary

Five problems are presented with their solutions.
1. Cutting a 10 × 5 rectangle from a 40 × 30 paper with four straight cuts to minimize total cut length yields an answer of 65.
2. Areas of simple hexagons A1B2A3B4A5B6 and B1A2B3A4B5A6 are equal due to division into 6 trapezoids with equal area triangles.
3. Angle CKB in a parallelogram with ∠D = 60◦, AD = 2, and AB = √3 + 1 is 75◦, found using Pythagoras theorem and angle bisector properties.
4. ∠O1AO2 + ∠O1BO2 > 90◦ for two circles with centers O1, O2 inside circle ω, tangent to ω, and on opposite sides of chord AB.
5. (a) It's possible for each segment to break exactly one other segment when extended.
(b) It's possible for all segments to be surrounded by exactly one segment that breaks them from both sides.

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Description

Five problems are presented with their solutions.
1.

Technical Information

File Format: PDF
File Size: 728 KB
Pages: 8
Language: EN
Total Downloads: 143
Last Updated: 1 month ago

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This PDF document about 5th IGO Problems provides comprehensive information and guidance. Whether you're a beginner or advanced user, this resource offers valuable insights into 5th IGO Problems.