Subtle Factorising.pdf

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Preview of Subtle Factorising
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Summary

Patrons are reminded that when they see 9x(x βˆ’1)2 βˆ’6x2(x βˆ’1) they should blur your eyes somewhat to see 9xz2 βˆ’6x2z. This clearly factories to 3xz(3z βˆ’2x) so the original factorises thus:
9x(x βˆ’1)2 βˆ’6x2(x βˆ’1) = 3x(x βˆ’1)[3(x βˆ’1) βˆ’2x] = 3x(x βˆ’1)(x βˆ’3).
Now factorise the following expressions fully.
1. x(x + 4) βˆ’3(x + 4) = (x + 4)(x βˆ’3)
2. 2x(x βˆ’3) + (x βˆ’3) = (x βˆ’3)(2x + 1)
3. 4(2x βˆ’1) + 3x(2x βˆ’1) = (2x βˆ’1)(3x + 4)
4. x(x + 2) + 2(x + 2) = (x + 2)2
5. 3x(y βˆ’1) + 2(y βˆ’1) = (y βˆ’1)(3x + 2)
6. p(x + y) + q(x + y) = (x + y)(p + q)
7. 4q(2x βˆ’y) βˆ’3p(2x βˆ’y) = (2x βˆ’y)(4q βˆ’3p)
8. 4x2(x + 2)2 βˆ’2x(x + 2) = 2x(x + 2)(2x2 + 4x βˆ’1)
9. 10x5(2x + 1) + 5x4(2x + 1)2 = 5x4(2x + 1)(4x + 1)
10. 49y(y βˆ’4)10 βˆ’35y2(y βˆ’4)9 = 14y(y βˆ’4)9(y βˆ’14)
11. (x + 1)4(x + 2) βˆ’2(x + 1)3(x + 2)2 = βˆ’(x + 2)(x + 1)3(x + 3)
12. 20(2x + 1)4(x βˆ’2)5 βˆ’25(2x + 1)5(x βˆ’2)4 = βˆ’5(6x + 13)(2x + 1)4(x βˆ’2)4
13. 16x2(x βˆ’1) βˆ’20x(x βˆ’1)2 = βˆ’4x(x βˆ’1)2
For the next few patrons are reminded that 3x(x + 1) / (x + 1)2 = 3x / (x + 1) and that factorising the top and bottom of a fraction is a wise way to proceed. Simplify the following:
14. (4x + 8) / (4) / (x + 2)
15. (7) / (14x βˆ’21) / (1) / (2xβˆ’3)
16. (3x + 6) / (5x + 10) / (3) / (5)
17. (x2 βˆ’4x) / (2x βˆ’8) / (x) / (2)
18. (4x + 2) / (6x2 + 3x) / (2) / (3x)
19. 2x(x + 1)2 / (x3 + x2) / (2(x+1)) / (x)
1

Description

Patrons are reminded that when they see 9x(x βˆ’1)2 βˆ’6x2(x βˆ’1) they should blur your eyes somewhat to see 9xz2 βˆ’6x2z.

Technical Information

  • File Format: PDF
  • File Size: 27 KB
  • Pages: 1
  • Language: EN
  • Total Downloads: 70
  • Last Updated: 1 week ago

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