Galvanic Cells & Redox Reactions.pdf

1. The half-cell reaction for Y(k) → Y+(suda) + e– has a potential of -1.60 V. Therefore, the answer is A.
2. In the given galvanic cell, electrons flow from the first anode to the second cathode. Thus, X > Y, making statement I true. The second half-cell is the cathode, so statement II is true. Adding water to the first cathode would decrease the potential, making statement III true. Therefore, the answer is E.
3. The incorrect statement is D. Al metal can react with a solution of Ni2+ ions, so it cannot be used to store such a solution.
4. In both setups, the reaction Zn(k) + Cu2+(suda) → Zn2+(suda) + Cu(k) occurs, making statement I true. In the second setup, an electric current is produced, making statement II true. Electron transfer occurs in both setups, making statement III true. Therefore, the answer is E.
5. The correct reaction is C: M + L2+ → M2+ + L. K can store MCI2, L cannot oxidize K, L can reduce M2+, and N reacts with LI2. Therefore, the answer is C.
6. In the given electrochemical cell, Zn is the anode, so statement I is true. In the B cell, the reaction Ag+(suda) + e– → Ag(k) occurs, making statement II true. Anions move towards the A cell, making statement III true. Therefore, the answer is E.
7. Standard electrode potential is affected by temperature and concentration, so the answer is C.
8. The initial potential of the given cell is -2.71 V. Therefore, the answer is D.
9. The standard starting potential of the given cell is 0.76 V. Adding Zn(NO3)2 to the first cell increases the potential, so statement B is false. Adding NaOH to the second cell decreases the potential, making statement C true. Adding pure water to the first cell increases the potential, making statement D true. Adding Cu(NO3)2 to the second cell does not change the potential, making statement E true. Therefore, the answer is B.
10. The cell potential is 0.25 V, making statement I true. The pH in the second cell decreases over time, making statement II true. The oxidation potential of Ni is 0.25 V, making statement III true. Therefore, the answer is E.